Difference between revisions of "Low-dropout regulator"

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A [[Low-dropout regulator]] ([[LDO]]) is a device which will regulate a stable voltage as long as the input voltage is "somewhat" higher (depends on the exact regulator) than the required output.
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[[File:Torex Semicon XC6206P332MR.png|thumb|Torex Semicon XC6206P332MR]]A [[Low-dropout regulator]] ([[LDO]]) is a device which will regulate a stable voltage as long as the input voltage is "somewhat" higher (depends on the exact regulator) than the required output.
  
 
It is important to know and understand that an [[LDO]] does this by "burning of" the excess voltage and this can and does result in quite a lot of heat which must be handled in the design.  The amount of energy burned off is easy to calculate.  Let's imagine using a 3.3V regulator from a 5V source.  The voltage drop over the regulator is 5V - 3.3V = 1.7V.  If using 100 mA that would result in 1.7V * 0.1A  = 0.17W (or 170 mW) of power.
 
It is important to know and understand that an [[LDO]] does this by "burning of" the excess voltage and this can and does result in quite a lot of heat which must be handled in the design.  The amount of energy burned off is easy to calculate.  Let's imagine using a 3.3V regulator from a 5V source.  The voltage drop over the regulator is 5V - 3.3V = 1.7V.  If using 100 mA that would result in 1.7V * 0.1A  = 0.17W (or 170 mW) of power.

Latest revision as of 03:52, 25 November 2020

Torex Semicon XC6206P332MR

A Low-dropout regulator (LDO) is a device which will regulate a stable voltage as long as the input voltage is "somewhat" higher (depends on the exact regulator) than the required output.

It is important to know and understand that an LDO does this by "burning of" the excess voltage and this can and does result in quite a lot of heat which must be handled in the design. The amount of energy burned off is easy to calculate. Let's imagine using a 3.3V regulator from a 5V source. The voltage drop over the regulator is 5V - 3.3V = 1.7V. If using 100 mA that would result in 1.7V * 0.1A = 0.17W (or 170 mW) of power.